It's an oblate spheroid with irregularities in height, not a perfect sphere. What rate of curvature should be able take into account all differences in height between mountain and canyon? Ok, that's unfair. But seriously, is there a rate of constant curvature that would account for even slight changes like rolling hills?
I just don’t care anymore to take the time for people who don’t take the time themselves
I’ve had many a discussion on the various dot win communities about it, and elsewhere
Your question was boring and uninformed
Eric Dubay has more than enough material on the subject if you care to earnestly explore someday
@Witsitgetsit is doing a flat earth debate on infowars in two days, maybe check that out or see his “Maskeraid tour” video which is a quick crash course and warm up to the subject
To answer your question about rate of curvature, it’s 8 inches per mile, squared
Square the mile not the 8, so it’s 8 inches of drop for the first mile then 32, 72, 128, 200, 288, 392, 512, 648, then 800 inches of drop at ten miles
We can do long distance observations across a span of water that far exceed ten miles they show zero drop
Distant buildings that should be fully obscured by the earth itself due to supposed curvature, in view, whether it be a hot summer day or a frozen winter day
If you live near a large body of water, I always recommend that one go see this for themselves
I can send you videos of others doing the same but it really hammers it home if you go see and test for yourself
Prove gravity
We demonstrate that the surface does not curve at the rate it must, given the dimensions we are given
How do you reconcile that
Prove gravity? Wow. Grab your camera, hop off a tall building then show us that you have disproved gravity. You own the burden of proof.
All that proves is that I’m denser than air
You said it, not me.
Mmmhmmm
Bumblebeetuna, fren
Be well
❤️
It's an oblate spheroid with irregularities in height, not a perfect sphere. What rate of curvature should be able take into account all differences in height between mountain and canyon? Ok, that's unfair. But seriously, is there a rate of constant curvature that would account for even slight changes like rolling hills?
You have the power of the interwebz in your hands
Plenty of info on our dot win communities if you actually care to look into it
That's what I thought
I just don’t care anymore to take the time for people who don’t take the time themselves
I’ve had many a discussion on the various dot win communities about it, and elsewhere
Your question was boring and uninformed
Eric Dubay has more than enough material on the subject if you care to earnestly explore someday
@Witsitgetsit is doing a flat earth debate on infowars in two days, maybe check that out or see his “Maskeraid tour” video which is a quick crash course and warm up to the subject
To answer your question about rate of curvature, it’s 8 inches per mile, squared
Square the mile not the 8, so it’s 8 inches of drop for the first mile then 32, 72, 128, 200, 288, 392, 512, 648, then 800 inches of drop at ten miles
We can do long distance observations across a span of water that far exceed ten miles they show zero drop
Distant buildings that should be fully obscured by the earth itself due to supposed curvature, in view, whether it be a hot summer day or a frozen winter day
If you live near a large body of water, I always recommend that one go see this for themselves
I can send you videos of others doing the same but it really hammers it home if you go see and test for yourself
Be well
❤️
Here's a crazy idea, how about you start a go fund me to build a weather balloon with a live feed camera and see for yourself
Already been done
Do you have a link to the video?