It's an oblate spheroid with irregularities in height, not a perfect sphere. What rate of curvature should be able take into account all differences in height between mountain and canyon? Ok, that's unfair. But seriously, is there a rate of constant curvature that would account for even slight changes like rolling hills?
I just don’t care anymore to take the time for people who don’t take the time themselves
I’ve had many a discussion on the various dot win communities about it, and elsewhere
Your question was boring and uninformed
Eric Dubay has more than enough material on the subject if you care to earnestly explore someday
@Witsitgetsit is doing a flat earth debate on infowars in two days, maybe check that out or see his “Maskeraid tour” video which is a quick crash course and warm up to the subject
To answer your question about rate of curvature, it’s 8 inches per mile, squared
Square the mile not the 8, so it’s 8 inches of drop for the first mile then 32, 72, 128, 200, 288, 392, 512, 648, then 800 inches of drop at ten miles
We can do long distance observations across a span of water that far exceed ten miles they show zero drop
Distant buildings that should be fully obscured by the earth itself due to supposed curvature, in view, whether it be a hot summer day or a frozen winter day
If you live near a large body of water, I always recommend that one go see this for themselves
I can send you videos of others doing the same but it really hammers it home if you go see and test for yourself
Why does the sun sink below the horizon at sea? On a flat plane where the sun orbits a central point, it would never set like that - only shrink to a distant point in the sky.
Yes, you can use a digital camera to see boats out at see that have disappeared to the human eye. What you leave out is that if you keep watching through the camera, the ship continues to disappear from the bottom up. What would cause that?
Edit: And as already discussed, 8 meters per square mile is a calculation for a smooth ball and not an oblate spheroid with many variations in elevation.
It's an oblate spheroid with irregularities in height, not a perfect sphere. What rate of curvature should be able take into account all differences in height between mountain and canyon? Ok, that's unfair. But seriously, is there a rate of constant curvature that would account for even slight changes like rolling hills?
You have the power of the interwebz in your hands
Plenty of info on our dot win communities if you actually care to look into it
That's what I thought
I just don’t care anymore to take the time for people who don’t take the time themselves
I’ve had many a discussion on the various dot win communities about it, and elsewhere
Your question was boring and uninformed
Eric Dubay has more than enough material on the subject if you care to earnestly explore someday
@Witsitgetsit is doing a flat earth debate on infowars in two days, maybe check that out or see his “Maskeraid tour” video which is a quick crash course and warm up to the subject
To answer your question about rate of curvature, it’s 8 inches per mile, squared
Square the mile not the 8, so it’s 8 inches of drop for the first mile then 32, 72, 128, 200, 288, 392, 512, 648, then 800 inches of drop at ten miles
We can do long distance observations across a span of water that far exceed ten miles they show zero drop
Distant buildings that should be fully obscured by the earth itself due to supposed curvature, in view, whether it be a hot summer day or a frozen winter day
If you live near a large body of water, I always recommend that one go see this for themselves
I can send you videos of others doing the same but it really hammers it home if you go see and test for yourself
Be well
❤️
Why does the sun sink below the horizon at sea? On a flat plane where the sun orbits a central point, it would never set like that - only shrink to a distant point in the sky.
Yes, you can use a digital camera to see boats out at see that have disappeared to the human eye. What you leave out is that if you keep watching through the camera, the ship continues to disappear from the bottom up. What would cause that?
Edit: And as already discussed, 8 meters per square mile is a calculation for a smooth ball and not an oblate spheroid with many variations in elevation.