For an example from my personal experience I can see a city thats 20-30 miles away. Laying down on the beach doesn't really change how much I can see so I'm not gonna bother with the eyesight level differences that the second calculator has, I'm gonna use the first.
So if I plug a number into this calculator, it spits out the amount an object should be hidden... From the bottom up according to the ball model.
20 miles: 0.05052 miles = 266.75 feet
30 miles: 0.11367 miles = 600.19 feet
So that means I shouldn't be able to see the bottom 266 feet of whatever is 20 miles away. I'm not sure exactly where they're getting that, as I can still see all of the beach on that opposing shore. Nothing at all looks like its hidden.
My city is 500 meters above sea-level, so it shows the horizon as 50mi away.
Thats....... not how that works. If you put in 500 meters for the altitude its like saying you're standing on a 500 meter tall building, not that the balls radius is 500m larger. The horizon is 50 miles away because you're up so high in relation to the radius of the earth. If you scroll down on that page they go over exactly all of the variables of the equation.
What's your reasoning for not seeing objects much further? Why can't I see the Alps from where I am?
Humidity. Eventually theres too much water to see through to get a clear picture of anything. This video goes over this concept in a little more depth.
Well you did leave this part out of the quote where I explained why this was incorrect to do. Edit: I see you edited in a comment on it
If you put in 500 meters for the altitude its like saying you're standing on a 500 meter tall building, not that the balls radius is 500m larger. The horizon is 50 miles away because you're up so high in relation to the radius of the earth.
The Calculator would have to have even more variables, altitude above sea level of viewing position and the position of what you're viewing for it to be even more accurate. You can see how that starts to get overly complicated when you get that specific. You probably couldn't even make a calculator out of it since you're not even using a simple ball anymore. They're using 3959 (r) as a constant just to make things simpler.
are you accounting for your geographic altitude (from sea-level) when you use that calculator?
In my original example of the cities, I checked the altitudes for both the place I am and the place I was viewing and they are the same altitude above sea level. If a 3959 mile radius ball (or whatever) is now 3959.5 that isn't gonna change a whole hell of a lot in the numbers. 266 feet is a lot. According to a quick search 1 "story" of a building is 14' tall. 266/14 = 19 Wheres the 19 story building hiding?
After the link not working and control F not turning up a 'earth-curvature' link on the page, I physically scanned down until I found this near the bottom:
Has some simple experiments to do that they claim will prove the earth is a ball. Haven't tried any, but the sunset twice method sounds like it has possibilities.
Not OP but I can reply about earth curvature calculations.
You can do a search and find earth curvature calculators such as these.
https://earthcurvature.com/
https://www.omnicalculator.com/physics/earth-curvature
For an example from my personal experience I can see a city thats 20-30 miles away. Laying down on the beach doesn't really change how much I can see so I'm not gonna bother with the eyesight level differences that the second calculator has, I'm gonna use the first.
So if I plug a number into this calculator, it spits out the amount an object should be hidden... From the bottom up according to the ball model.
20 miles: 0.05052 miles = 266.75 feet
30 miles: 0.11367 miles = 600.19 feet
So that means I shouldn't be able to see the bottom 266 feet of whatever is 20 miles away. I'm not sure exactly where they're getting that, as I can still see all of the beach on that opposing shore. Nothing at all looks like its hidden.
Thats....... not how that works. If you put in 500 meters for the altitude its like saying you're standing on a 500 meter tall building, not that the balls radius is 500m larger. The horizon is 50 miles away because you're up so high in relation to the radius of the earth. If you scroll down on that page they go over exactly all of the variables of the equation.
Humidity. Eventually theres too much water to see through to get a clear picture of anything. This video goes over this concept in a little more depth.
Why Can't Everyone See Mount Everest on a Flat Earth? [3mins 5 seconds] - https://www.youtube.com/watch?v=RqvH0Y1L41s
Well you did leave this part out of the quote where I explained why this was incorrect to do. Edit: I see you edited in a comment on it
The Calculator would have to have even more variables, altitude above sea level of viewing position and the position of what you're viewing for it to be even more accurate. You can see how that starts to get overly complicated when you get that specific. You probably couldn't even make a calculator out of it since you're not even using a simple ball anymore. They're using 3959 (r) as a constant just to make things simpler.
In my original example of the cities, I checked the altitudes for both the place I am and the place I was viewing and they are the same altitude above sea level. If a 3959 mile radius ball (or whatever) is now 3959.5 that isn't gonna change a whole hell of a lot in the numbers. 266 feet is a lot. According to a quick search 1 "story" of a building is 14' tall. 266/14 = 19 Wheres the 19 story building hiding?
Fake and gay shills talking to eachother.
Fake conversations.
Fake discussion.
Fake debate.
Fake issue.
This is not found, and the link including it fails. The site itself is up, but that specific element has been removed or broken.
Works for me. Just google “earth curvature calculator” there’s more of them
After the link not working and control F not turning up a 'earth-curvature' link on the page, I physically scanned down until I found this near the bottom:
https://www.omnicalculator.com/physics/flat-vs-round-earth
Has some simple experiments to do that they claim will prove the earth is a ball. Haven't tried any, but the sunset twice method sounds like it has possibilities.