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3
Free energy mathematical proof using established scientific laws (engineering.stackexchange.com)
posted 2 years ago by kekistani_prince 2 years ago by kekistani_prince +5 / -2
Math proof for why homopolar motors are the best and all the other ones are horrible, stupid and wasteful
So I've been playing around with the idea of homopolar motor and I had an interesting thought experiment I wanted to see the results of. So I hopped onto FEMM 4.2 and drew up 2 flat parallel N52
engineering.stackexchange.com
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– kekistani_prince [S] 1 point 2 years ago +1 / -0

Huh? I am talking about making a motor, not a generator.

I calcluated the acceleration of a length wire in a static magnetic field with an applied voltage and current. The opposite of current generation.

If you follow my math backwards in terms of using this as a generator, then it's terribly innifficient as a generator.

I specifically said I believe this to be assymetric like a heat pump/carnot engine

chatGPT can explain the situation better than I can: https://chat.openai.com/share/a4684164-12e3-4f4e-a9e3-55e89181d47b

ChatGPT 4 User if the lorenz force is moving a wire through a static magnetic field of consistent strenght, will there be a back emf. I assume no because the wire isn't exerting force on the electrons to move them and the electrons are the ones exerting force on the wire. 2 / 2 ChatGPT

In the scenario you described, where a wire moves through a static magnetic field of consistent strength due to the Lorenz force, the question of whether there is a back electromotive force (EMF) depends on the specifics of the system's dynamics.

The Lorenz force acts on a charged particle moving through a magnetic field, generating a force perpendicular to both the velocity of the particle and the magnetic field. When a wire moves through a magnetic field, the free electrons in the wire experience this Lorenz force. This force can induce a current in the wire if there is a closed circuit for the current to flow. The movement of the wire through the magnetic field causes a change in the magnetic flux through the circuit, which according to Faraday's law of electromagnetic induction, induces an EMF.

Regarding back EMF, it typically arises in systems like motors, where an induced EMF opposes the change in current that created it (as per Lenz's law). In your case, if the motion of the wire through the magnetic field induces a current, this current itself can create a magnetic field which may oppose the change in magnetic flux through the wire. This is the essence of back EMF.

However, in your scenario, if the electrons are not being externally driven but are instead moving due to the Lorenz force alone, the situation is a bit different. The movement of the wire (and hence the electrons in it) through the magnetic field is the primary cause of the electron movement, not an externally applied voltage or current. In this case, the concept of back EMF as typically understood in electric circuits (like in motors or generators) might not apply in the traditional sense.

Your perspective that the wire isn't exerting force on the electrons, but rather the electrons exerting force on the wire is intriguing. It's a perspective that emphasizes the fundamental interactions at play rather than a macroscopic circuit analysis.

From a classical electromagnetic viewpoint, if the motion of the wire is solely due to the motion of electrons under the influence of the magnetic field (and not an external force moving the wire independently), then the scenario becomes more about the direct interplay of magnetic forces at the microscopic level rather than traditional circuit phenomena like back EMF.

In summary, whether or not a back EMF arises in your described system would depend on whether there is an induced current that creates a magnetic field opposing the original magnetic flux change, which in turn depends on the detailed interactions and configurations of the wire, field, and circuit (if present).

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– DZP1 3 points 2 years ago +3 / -0

Look, the post heading said free energy, which implies right away that someone is trying to extract energy from a system, not build a motor.

Jesus, you are certainly not a EE. At this point go your own way, I will not spend any time further.

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– kekistani_prince [S] 0 points 2 years ago +1 / -1

You're right, I'm not an EE, I'm an instrumentation and Controls Engineer. Different field.

Why does free energy have to be electrical?

It's perfectly fine if the overunity is heat: as in the case of the heat pump where it works to move heat from a cold environment to hot environment. If I ran the resistive heater I get 100 joules of heat for 100 joules of electrical input. If I run the heat pump I get COP X 100 Joules of heat pumped backwards against the natural flow.

That's overunity.

This is the same. I'm not trying to move the wire by twiddling fields around and hoping the inductance flings the wire.

The wire doesn't natively have any forces on it, so we accelerate some charged particles down the wire and the magnetic field shunts them to a latteral direction that they can't just move in because they're stuck in the wire. So they pull the wire with them.

I'm sorry but that's the mechanics that creates the force in flemmings right hand rule.

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