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3
How can the moon appear "upside down" when viewed from what the rest of us call "the southern hemisphere" on a flat Earth? (media.scored.co)
posted 3 years ago by LightBringerFlex 3 years ago by LightBringerFlex +9 / -6
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– Allas8 1 point 3 years ago +1 / -0

Distance that we are given from the north pole to the south pole is 12400 miles, so you can times that with two. So the diameter of the known flat earth, is around 24800 miles. While the height of the moon would be at around 3000 miles above the earth. Good luck with the checking.

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– ChippingToe 1 point 3 years ago +1 / -0

I'm on mobile now but i did some calculations, i can upload pictures later.

But given those parameters, a person standing anywhere on the south pole (which i understand to be any point in the outer edge of the disc) at sea level, and a moon that is at the opposite side of the disc (~25K miles away from the person) and 3K miles above sea level, the smallest angle possible is about 6.8 degrees, not 0.01.

But that's not necessarily conclusive, we just have to figure out what it would take to obstruct this person's view of the moon in this scenario, since this is the worst case scenario (the furthest a person can be from the moon while still on the flat earth.

So what could block this guy's view of the moon? Well, if he's 6ft tall then any 7ft obstacle could do it, IF right in front of him. In the other extreme, any 3001 mile obstacle could also block his view of the moon, even if said obstacle was at the opposite side of the disc.

So what's the tallest possible obstacle? Mt Everest at 5.5 miles. Doesn't seem like much, and after some math it clearly isn't. Given the scenario above, even mount Everest itself would not be tall enough to block your view of the moon, unless it was within 45 miles of you. In other words, if you are 46 miles away from mt everest, then it won't block your view of the moon, even if the moon was as far away as could be.

Now there could be less tall obstacles than mt everest that could still block your view, provided that they are closer. But still, 45 miles is a very small area. Given these numbers, you could go to any point in the ocean that is 4 miles from any shore, and the moon would always be visible from there (because 45 miles from the shore means Everest is even farther, and you're at sea so there's nothing else out there to obstruct your view). There are hundreds of places that you could visit to test that theory. Thousands.

But even putting all this math aside, I realized that your model would also imply that the moon is always visible from the tallest point on earth. Because there's nothing blocking you. But this is clearly not the case, or at least i don't think you belive that but please tell me if I'm wrong.

Tldr i don't think your model aligns with observable reality.

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– Allas8 1 point 3 years ago +1 / -0

Your calculations is based on a side view, not from the perspective of the person.

All parallel lines going away from you will converge to a point in the distance, where the ground meets the sky, or appears to. The horizon will rise to eye level at about 3 miles away from you, when standing on the ground. This is how perspective works.

Here is a video of p-brane explaining this to you. Watch it if you want:

THE SUN SETS JUST FINE ON A FLAT EARTH - THE MATHS ARE WRONG perspective

https://youtu.be/W0Gx1vD1CRE

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– ChippingToe 1 point 3 years ago +1 / -0

Why are you now bringing perspective into this? Yes there are dozens of concepts that appear to support the flat earth theory on the surface, but you don't get to jump from one to the other as they each fail under scrutiny.

I know how perspective works. Now tell me what could possibly obstruct your line of sight of the moon from atop Everest.

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– Allas8 1 point 3 years ago +1 / -0

The horizon, as it rises to eye level. The horizon will always rise to eye level

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