Because you can only see ISS when it reflects the suns light.
Here is one reason why the distances, direction, size and relative speed of the celestial objects is important.
The moon's monthly phases, clearly show that the moon makes a single rotation in a month, as shown by the phases of the moon. Most importantly the Moon's phases show that the Sun isn't moving in relation to the Moon (this is important). The lit up portion of the moon tells us the direction of the Sun to the Moon. Triangulating that angle between the Moon, Sun and Earth will provide the distance to the Sun.
We also know that both the Moon and the Sun, cross the sky in exactly the same 12 hour period. The Stars also cross the sky in exactly the same 12 hour period.
The only mathematical solution with the above physical constraints is that the Earth is rotating in space and the Moon is orbiting the Earth once a month.
From what I can tell, the FE theory doesn't answer any of those equations.
I want to know the FE's estimation of the distance of the sun, moon and stars above the earth and why their transit time across the sky is always identical? How is that possible?
Bonus question, how do the stars rotate around the North Star which is in a fixed position and doesn't move at all.
I have been above the Arctic circle during the Summer Solstice and watched the Sun circle low on the horizon completely around me never rising or setting. How does the FE model explain that? Both the stars and sun also do a complete rotation in a 24 hour period, with both the sun and the stars staying in the same relative position with each other?
I think that is an excellent question for Glowies_love_me to answer.
Because you can only see ISS when it reflects the suns light.
Here is one reason why the distances, direction, size and relative speed of the celestial objects is important.
The moon's monthly phases, clearly show that the moon makes a single rotation in a month, as shown by the phases of the moon. Most importantly the Moon's phases show that the Sun isn't moving in relation to the Moon (this is important). The lit up portion of the moon tells us the direction of the Sun to the Moon. Triangulating that angle between the Moon, Sun and Earth will provide the distance to the Sun.
We also know that both the Moon and the Sun, cross the sky in exactly the same 12 hour period. The Stars also cross the sky in exactly the same 12 hour period.
The only mathematical solution with the above physical constraints is that the Earth is rotating in space and the Moon is orbiting the Earth once a month.
From what I can tell, the FE theory doesn't answer any of those equations.
Your 'answer' was completely non responsive.
I want to know the FE's estimation of the distance of the sun, moon and stars above the earth and why their transit time across the sky is always identical? How is that possible?
Bonus question, how do the stars rotate around the North Star which is in a fixed position and doesn't move at all.
I have been above the Arctic circle during the Summer Solstice and watched the Sun circle low on the horizon completely around me never rising or setting. How does the FE model explain that? Both the stars and sun also do a complete rotation in a 24 hour period, with both the sun and the stars staying in the same relative position with each other?